Math, asked by abhikrishnaktr, 9 months ago

One side of a rhombus is 12 cm and one angle is 135

a)Find the distance between the parallel sides.

b) Find area of the rhombus.​

Answers

Answered by amitnrw
3

Given : One side of a rhombus is 12 cm and one angle is 135°.

To Find : a)   the distance between the parallel sides?

b)  the area of the rhombus.

Solution:

Side of Rhombus = 12 cm

one angle = 135°

adjacent angle = 180° - 45°

Using cosine rule 4

Diagonals  = √(12² + 12² - 2*12*12Cos135°)     ,  √(12² + 12² - 2*12*12Cos45°)

  Cos135° = -1/√2   Cos45° =  1/√2

√(12² + 12² - 2*12*12Cos135°)   = 12√(1 + 1 +√2)  = 12√(2+√2)

√(12² + 12² - 2*12*12Cos45°) = 12 √(2 -√2)

Area of Rhombus = (1/2) *   12√(2+√2) * 12 √(2 -√2)

= 72√( 4 - 2)

=72√2 cm²

Rhombus is parallelogram also

area of Parallelogram = Base * height

height = distance between the parallel sides

=> 72√2 = 12 * height

=> height = 6√2 cm

distance between the parallel sides   = 6√2 cm

Area of Rhombus = 72√2 cm²  

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