Question

One side of a rhombus is 20 cm and one of the diagonals is 24 cm. Find the area of the rhombus.​

Answer 1

Step-by-step explanation:

that's your answer in the above picture

Answer 2

Answer:

The diagonals of a rhombus bisect at right angles.

Consider Δ AOD

Using the Pythagoras theorem,

AD^2 = OD^2 + AO^2

By substituting the values,

20^2 = OD^2 + 12^2

On further calculation,

OD^2 = 400 − 144

By subtraction,

OD^2 = 256

By taking out the square root,

OD =

$\sqrt{256}$

So we get,

OD = 16cm

We know that BD = 2OD

So we get

BC = 2 (16) = 32cm

We know that,

Area of rhombus ABCD = 1/2 × AC × BD

By substituting the values,

Area of rhombus ABCD = 1/2 × 24 × 32

On further calculation,

Area of rhombus ABCD = 384cm^2

Therefore, the area of rhombus ABCD is 384cm^2.

Hope it helped you..

Thank you !!!