Question

One side of a right angled triangle is 20 cm and the difference in length of its hypotenuse and other side is 8 cm find the other side and area of the triangle

Answer 1

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Answer 2

The area of triangle is 210 sq.cm.

Step-by-step explanation:

Let the one side be x cm

We are given that the difference in length of its hypotenuse and other side is 8 cm

So, Hypotenuse = x+8

Other side of right angled triangle = 20 cm

$Hypotenuse^2 = Perpendicular^2+Base^2 \\(x+8)^2 = x^2+20^2 \\x^2+16x+64=x^2+400 \\16x+64=400 \\16x=336$

x=21

Hypotenuse = x+8= 21+8 = 29 cm

Area of right angled triangle  =$\frac{1}{2} \times Base \times Height = \frac{1}{2} \times 20 \times 21 =210 sq.cm.$

Hence The area of triangle is 210 sq.cm.

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One side of a right angled triangle is 20 cm and the difference in length of its hypotenuse and other side is 8 cm find the other side and area of the triangle

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