one side of a right angled triangle is 20cm and the di
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Let one of the sides be x then another side is 4 + x. Applying Pythagoras theorem (20)² = (x)² + (x + 4)² 400 = x² + x² + 8x ...
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One side of triangle is 20cm
Let other side be (x) and hypotenuse be (x + 8)
(x)^2 + (20)^2 = (x+8)^2 [Pythagoras theorem]
x^2 + 400 = x^2 + 16x + 64
16x = 336
x = 21cm
second side = x = 21 cm
Hypotenuse = x + 8 = 29 cm
Area of ∆ = 1/2 × b × h
= 1/2 × 20 × 21
= 210 cm^2
Hope this helps... plsss make it the brainliest
Let other side be (x) and hypotenuse be (x + 8)
(x)^2 + (20)^2 = (x+8)^2 [Pythagoras theorem]
x^2 + 400 = x^2 + 16x + 64
16x = 336
x = 21cm
second side = x = 21 cm
Hypotenuse = x + 8 = 29 cm
Area of ∆ = 1/2 × b × h
= 1/2 × 20 × 21
= 210 cm^2
Hope this helps... plsss make it the brainliest
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