Question

one side of a right triangle is 8cm and the difference between other two sides is 4 cm . Find its area by Herons formula​

Answer 1

Step-by-step explanation:

Let the hypotenuse be 8 cms.

Acc. to question, the other two sides are x and x+4.

Using Pythagoras Theorem,

x^2 + (x-4)^2 = 64

Solve the equation, find the value of x. YOU WILL GET TWO VALUES OF x.

Eliminate the negative value.

Then find the sides and apply Herons Formula.

Answer 2

One side of a right triangle is 8 cm and the difference between other two sides is 4 cm. find its area by heron’s formula.

..

using Pythagoras theorem

let hyp = x

side1 = x-4

side 2 = 8

..

x^2= (x-4)^2+64

x^2=x^2-8x+16+64

8x=16+64

8x=80

x=10 cms

--

side 1 = 8 cm.

side 2 = 10 cm.

side 3 = 10-4 cm.=6cm

..

area = sqrt(s(s-a)(s-b)(s-c))

s= 10+8+6 /2

s=24 /2

s= 12

..

Area = sqrt{12(12-8)(12-10)(12-6)

Area = sqrt{12(4)(2)(6)}

Area = sqrt{576}

Area = 24 sq. cm.

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