Question

One side of a square is 8cm . Find the lenth of its dignol using pythagorean triplet

Answer 1

QUESTION:

One side of a square is 8cm . Find the lenth of its dignol using pythagorean triplet.

ANSWER:

We know that;

all the sides of the square are equal.

And all the angles are right angles that is 90°.

Refer the attachment for the figure;

we have to find AC.

AB = BC = 8 CM.

We use the pythagorean formula here;

$\huge\red{AC = \sqrt{ {AB}^{2} - {BC}^{2} }}$

now come to main question;

$AC= \sqrt{ {8}^{2} + {8}^{2} } \\ AC = \sqrt{64 + 64} \\ AC = \sqrt{128} \\ AC = 8 \sqrt{2} cm$

FINAL ANSWER :

$\huge\red{8 \sqrt{2} cm}$

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