One side of a square is increased by 2 m and the other side is reduced by 2 m. Then a rectangle is formed whose perimeter is 48 m. Find the side of the original square.
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HERES UR ANSWER
LET THE BOTH SIDE OF SQUARE BE X M.
A/q
first side = X + 2 m. {leads to the formation
another side = x - 2 m. of rectangle }
LET THE FIRST SIDE BE LENGTH
AND THE SECOND ONE BE BREADTH
AS WE KNOW THAT
AREA OF RECTANGLE = LENGHT × BREADTH
48m² = x + 2m × x - 2m.
48m² = x × x = 2x
2x = 48m²
x = 48/2
x = 12 m.
DONE
HERES UR ANSWER
LET THE BOTH SIDE OF SQUARE BE X M.
A/q
first side = X + 2 m. {leads to the formation
another side = x - 2 m. of rectangle }
LET THE FIRST SIDE BE LENGTH
AND THE SECOND ONE BE BREADTH
AS WE KNOW THAT
AREA OF RECTANGLE = LENGHT × BREADTH
48m² = x + 2m × x - 2m.
48m² = x × x = 2x
2x = 48m²
x = 48/2
x = 12 m.
DONE
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