Question

one side of a triangle is 12 cm and two of its angles are 45° and 60? 1.find the length of other 2 sides of the triangle 2.find the perimeter of the triangle​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

1.sin 45 = 1/$\sqrt{2}$

sin theta = opposite side/hypotenuse

opposite side/hypotenuse = 1/$\sqrt{2}$

12/hypotenuse = 1/$\sqrt{2}$

hypotenuse = 12$\sqrt{2}$

cos 45 = 1/$\sqrt{2}$

adjacent side/hypotenuse = 1/$\sqrt{2}$

adjacent side/12$\sqrt{2}$ = 1/$\sqrt{2}$

adjacent side = 12

Therefore the sides are 12,12,12$\sqrt{2}$

2.Perimeter = 12+12+12$\sqrt{2}$ = 24+12$\sqrt{2}$ = 24 + 12(1.414) =24 + 16.9 = 40.9cm

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