Math, asked by newboygaming0987, 1 day ago

one side of a triangle is 12 cm and two of its angles are 45° and 60? 1.find the length of other 2 sides of the triangle 2.find the perimeter of the triangle​

Answers

Answered by nanhelal3232
0

Answer:

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Step-by-step explanation:

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Answered by sivaswethbe
0

Step-by-step explanation:

1.sin 45 = 1/\sqrt{2}

sin theta = opposite side/hypotenuse

opposite side/hypotenuse = 1/\sqrt{2}

12/hypotenuse = 1/\sqrt{2}

hypotenuse = 12\sqrt{2}

cos 45 = 1/\sqrt{2}

adjacent side/hypotenuse = 1/\sqrt{2}

adjacent side/12\sqrt{2} = 1/\sqrt{2}

adjacent side = 12

Therefore the sides are 12,12,12\sqrt{2}

2.Perimeter = 12+12+12\sqrt{2} = 24+12\sqrt{2} = 24 + 12(1.414) =24 + 16.9 = 40.9cm

I hope it help please mark me as brainliest...

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