Math, asked by rushi12333, 7 months ago

*One side of a triangle is 3 metres more than twice its base, and the other side is 9 metres more than the base. If the perimeter of the triangle is 48 m, the side lengths of the triangle are ______.*

1️⃣ 11 m, 17 m and 20 m.
2️⃣ 21 m, 7 m and 20 m.
3️⃣ 9 m, 18 m and 21 m.
4️⃣ 14 m, 19 m and 25 m.​

Answers

Answered by adithyarajiv3
0

Answer:

option 3

Step-by-step explanation:

let the length of base be x m.

then according to the info given in the question,

the sides of triangle are x, 2x+3&  x+9 m .

perimeter = sum of all sides

48=x+2x+3+x+9

solving the equation we get x=9 m

substituting value of x we get the sides as 9 m,  21m & 18 m.so option 3 is correct

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