*One side of a triangle is 3 metres more than twice its base, and the other side is 9 metres more than the base. If the perimeter of the triangle is 48 m, the side lengths of the triangle are ______.*
1️⃣ 11 m, 17 m and 20 m.
2️⃣ 21 m, 7 m and 20 m.
3️⃣ 9 m, 18 m and 21 m.
4️⃣ 14 m, 19 m and 25 m.
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Answer:
option 3
Step-by-step explanation:
let the length of base be x m.
then according to the info given in the question,
the sides of triangle are x, 2x+3& x+9 m .
perimeter = sum of all sides
48=x+2x+3+x+9
solving the equation we get x=9 m
substituting value of x we get the sides as 9 m, 21m & 18 m.so option 3 is correct
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