Question

One side of a triangle is ' s' cm. The second side is 8 cm more than the first side. The third side is 4 cm less than the first side. Write the algebraic expressions for all the sides​

Answer 1

Answer:

Let first side of triangle = x

second side of triangle = x+8

Third side of triangle = x-4

x+(x+8)+(x-4) =180

3x+4 = 180

3x = 180-4

3x = 176

x = 176/3

first side of triangle =176/3

second side of triangle = 176/3 + 8

= 200/3

Third side of triangle = 176/3 - 4

= 164/3

Thanks for asking this question