Question

one side of an equilateral triangle is 4cm. find its area

Answer 1

area=√3/4×(s)*2
=√3/4*4×4
=√3×4
=1.73×4
=6.92cm*2

Answer 2

Using Heron's formula

a+b+c/2. Here a,b,and c are the sides of the triangle

a=b=c= 4

4+4+4/2

12/2

6= s or semi permeter

√s{s-a}{s-b}{s-c}

√6(6-4)(6-4)(6-4)

√6×2×2×2

√3×2×2×2×2

2×2√3

4√3

Substituting the value of √3

4 × 1.732

6.928 it is the area of triangle