Question

one side of an equilateral triangle measures 16 cm find its area and its altitude ​

Answer 1

Answer:

simple

Step-by-step explanation:

Let ABC b a triangle

draw AD as an altitude of it, so that it divides the base BC into two equal segments.

Now dear, there r two triangles ABD and ACD.

IN triangle ABD 1 side = 16cm base side = 8cm third side =?

using Pythagorean theorem

B^2+P^2=H^2

8^2+P^2 =16^

P=13.85

ar(ABC)= 1/2( B×H)

1/2(16×13.85)= 110.8cm^2

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