Question

one side of an equilateral triangle measures 16 cm find its area and its altitude ​

Answer 1

Answer:

area=root3/4×16square

Answer 2

Answer:

$area \: of \: eq \: triangle = \frac{ \sqrt{3} }{4} {side}^{2} \\ = \frac{ \sqrt{3} }{4} \times 16 \\ = 4 \sqrt{3} {cm}^{2} \\ height \: of \: eq \: triangle = \frac{ \sqrt{3} }{2} side \\ = \frac{ \sqrt{3} }{2} \times 16 \\ = 8 \sqrt{3} cm$