One side of an isosceles triangle is 15 if the perimeter of triangle is 55 then the length of each of its equal side is
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let say A, B, C is an isosceles triangles with 15 = BC and AB =AC
then
perimeter = 55
perimeter of triangle = AB+BC+CA
55 = AB+AB+15 (since AB=AC)
55=2AB +15
2AB=55-15
AB=40/2
AB=20=AC (equal sides)
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