Math, asked by mithilesh9929, 9 months ago

One side of the bottom layer of a triangular pyramid has 12balls. How many are there in the whole pyramid? Note that the pyramid is equilateral and solid.​

Answers

Answered by kajusona
1

Answer:

Bottom layer contains (12+11+10+...+1) = 12*13/2 = 78 balls.

Immediate top layer contains (11+10+...+1) = 66 balls.

Similarly, the number of balls in the layers from top to bottom are 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, 66, 78. Total = 1+3+6+10+15+21+28+36+45+55+66+78 = 364 balls

Step-by-step explanation:

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