Question

One side with 60cm and one rectangular field with length 80cm have the same perimeter . Which field has a larger area ?​

Answer 1

Answer:

60 ×80

=4,800 cm

Step-by-step explanation:

here your answer plz thanks my answer

Answer 2

$\large\underline{ \underline{ \sf \maltese{ \: Question:- }}}$

• One side with 60cm and one rectangular field with length 80cm have the same perimeter . Which field has a larger area ?

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$\large\underline{ \underline{ \sf \maltese{ \: Given:- }}}$

• Let l be the length and b be the width of the rectangular field.
• Length = 80cm
• Side of Square = 60cm
• Perimeter of Rectangle = Perimeter of Square

$\large\underline{ \underline{ \sf \maltese{ \: </strong><strong>Solution</strong><strong>:- }}}$

$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\:2( \: l \: + \: b \: ) \: = \: 4( \: Side \: ) }} }\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\qquad \quad {:} \longrightarrow \sf{\sf{2( \: 80\: + \: b \: ) \: = \: 4 \times 60 \: }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ 160\: + \:2 b\: = \: 240 }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{\:2 b\: = \: 240\: - \: 160 }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{\:2 b\: = \: 80 }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{\: b\: = \: \frac{80}{2} }}$

$\qquad \quad {:}\longrightarrow\sf{\sf{ b \: = \: \cancel\frac{80}{2} }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{Breadth \: = \: 40m }}}$

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$\underbrace\red{\boxed{ \sf \green{ Area \: of \: the \: Square \: Field }}}$

$\quad {:} \longrightarrow \sf{\sf{\:( \: side \: )^{2} }}$

$\quad {:} \longrightarrow \sf{\sf{\:( \: 60 \: )^{2} }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{Area \: of \: Square \: = \: 3600 {m}^{2} }}}$

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$\underbrace\red{\boxed{ \sf \green{ Area \: of \: the \: Rectangular \: Field }}}$

$\quad {:} \longrightarrow \sf{\sf{\:L \: \times \: B }}$

$\quad {:} \longrightarrow \sf{\sf{\:\: 80 \: \times \: 40 }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{Area \: of \: Rectangle \: = \: 3200 {m}^{2} }}}$

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We can clearly see that the Area of Square Field is larger

• 3600 > 3200

$\bf \therefore \; Area \;of \; Square \: Field \: is \: larger$

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$\large\underline{ \underline{ \sf \maltese\red{ \: Diagram:- }}}$

Square:-

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(4,0){2}{\line(0,1){4}}\multiput(0,0)(0,4){2}{\line(1,0){4}}\put(-0.5,-0.5){\bf D}\put(-0.5,4.2){\bf A}\put(4.2,-0.5){\bf C}\put(4.2,4.2){\bf B}\put(1.5,-0.6){\bf\large 60\ cm}\put(4.4,2){\bf\large 60\ m}\end{picture}$

Rectangle:-

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 80 m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 40 m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

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