Question

One-sixth of a stick is cut off and then three-tenths of the remaining piece is thrown away. What fraction of the original stick remains?

Answer 1

Answer:

If 1/6 of a stick is cut off and from the remaining 3/10 is thrown away, then 8/15 of the stick is remaining

Step-by-step explanation:

From 1 full portion of a stick, 1/6 th was cut off

That is, the remaining part is

$1-\frac{1}{6} \\\\=\frac{5}{6}$

Then, 3/10 of the remaining is thrown away

Then the remaining part is,

$\frac{5}{6} -\frac{3}{10} \\\\\\=\frac{(5*10)-(3*6)}{6*10} \\\\= \frac{50-18}{60}\\\\=\frac{32}{60} \\\\=\frac{8}{15}$

So, $\frac{8}{15}$ part is remaining