Question

One solid sphere of mass 1 kilogram and diameter 0.3 suspended from wire if two string couple per unit used for wire is 6 into 10 power minus 2 then the time period of torsional Pendulum

Answer 1

One solid sphere of mass 1 kilogram and diameter 0.3 suspended from wire if two string couple per unit used for wire is 6 into 10 power minus 2 then the time period of torsional Pendulum

Explanation:

 = 2π  √2/k                                                

= 2π√(9*10⁻³)  / (6*10⁻³)

=2π√³/₂

=7.7 seconds

2/5Mr²

= 2/5 (1) (0.3/2)²

0.09/10

= 9*10⁻³