Question

one solution 2x^2-x-1=0​

Answer 1

LHS=

$2 {x}^{2} - 2x + x - 1$

$2x(x - 1) + 1(x - 1)$

$(x - 1)(2x + 1)$

Therefore x-1=0 OR 2x+1=0

Therefore, x=1. OR. x= -1/2

Therefore, roots of quadratic equation are 1, -1/2.

Hope it helps ^_^