Question

one solution of the quadratic equation 2x^2-5x-3=0 find x=?
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Answer 1

Answer:

2x^2-6x+x-3

2x(x-3) +1(x-3)

(x-3) (2x+1)

Applying Zero product rule

if (x -3) = 0

x = 3(Answer)

if(2x -1) = 0

x = 1/2.(Answer)