Question

One stone is dropped from a height of 500m.From the ground, another stone is thrown up with a velocity of 30m/s.When and where the two stones will meet?

Answer 1

Answer:

ans =6 sec

Explanation:

at t sec stone covers x distance since it is dropped u=0

then x= 1/2 gt^2

at the same time a ball thrown upwards then the distance covered by this stone is

500-x  =30t +1/2gt^2

adding these two equations we get

500= 30t

t=6 sec