One student uses a lens of focal length +50cm and another of -50cm. State the nature and find the power of each lens. Which of the two lenses will always give a virtual and diminished image irrespective of the position of the object?
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Answer:
focal length is always in metre so therefore
50cm =0.5m
when focal length is -0.5m means the lens is concave
P=1/f
P=1/0.5
P=1×10/5
P= 2.0 ( the focal length of the lens is in negative which means the lens is concave and the power of concave lens is always negative)
P=-2.0D
When focal length is +50cm
50cm =0.5m
P=1/f
P=1/0.5
P=1×10/5
P=2.0+ ( the focal length of the lens is positive which means the lens is convex and its power is always positive)
P=+2.0 D
Explanation:
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