Math, asked by shaikhsadiyaparvin, 8 months ago

One tap can fill a cistern in 3 hours and the waste pipe can empty the full tank in 5 hours. In what time empty cistern be full, if the tap and the waste pipe kept open together ​

Answers

Answered by SonalRamteke
27

keeping smiling

One tap can fill a cistern in = 3 hours

Waste pipe can empty a cistern in = 5 hours

∴ One tap 1 hour work = 1/3

Waste pipe 1 hour work = 1/5

∴ One tap and waste pipe together 1 hour work

= 1/3 – 1/5 = (5 – 3)/15

= 2/15

∴ Empty cistern will be full in 15/2 hours

= 7. ½ hours

I hope I help you dear plz mark as a brain list plz

Answered by stelladaniel216
3

Answer:

The solution is illustrated in the picture attached.

Step-by-step explanation:

The step by step solution is illustrated in the picture attached.

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