Math, asked by justinsmith8736, 3 months ago

one tap can fill a cistern in 5 hours and another in 6 hours .if both the taps Starts filling the cistern simultaneously then in how much time the cistern will be filled​

Answers

Answered by asahilthakur
7

Answer:

2 whole 8/11 hours

Step-by-step explanation:

Time taken by first tap = 5 hours

Work done by first tap in 1 hour = 1/5

Time taken by second tap = 6 hours

Work done by second tap in 1 hour = 1/6

Work done by both in 1 hour = 1/5 + 1/6 = (6+5) / 30 = 11/30

Hence, both taps will fill the tank in 30/11 (or 2 whole 8/11) hours.

Similar questions