Question

One tap can fill a tank 10 hours. And another tap can empty the tank in 15 hours. How much time does it take to fill the tank if both pipes are opened ?

Answer 1

LET 1 ST TAP BE A AND 2 ND BE B .

A CAN FILL A TANK IN 10 HOURS .

SO IN 1 HOUR A CAN FILL 1/10 OF THE TANK.

B CAN FILL THE TANK IN 15 HOURS .

SO IN 1 HOUR B CAN FILL 1/15 OF THE TANK.

A AND B TOGETHER =

=1/10 + 1/15 ( LCM =30)
=3/30 + 2/30
=5/30
=1/6
=6

ANSWER A AND B CAN FILL THE TANK TOGETHER IN 6 HOURS...

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Answer 2

hey mate !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

time taken by one tap to fill in 1 hour= 1/10

time taken by another tap to empty in 1 hr= 1/15

time taken by both the pipes to fill the tank in 1 hour= 1/10-1/15

                                                                                  =1/30 hours

total time taken =30 hour

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