Question

One tap fills a tank in 12 min. and another tap fills it in 15 min. The waste-pipe can empty the tank
in 10 min. In what time will the tank be filled, if both are turned on and if the waste pipe has been left
open accidentally?​

Answer 1

Answer:

20 mins

Step-by-step explanation:

for tap 1st

work done in 1 min = 1/12 part of work

for tap 2nd

work done in 1 min = 1/15 part of work

for tap 3rd

work done in 1 min = -1/10 part of work

work done in 1 min together tap = 1/12+1/15-1/10

= (5+4-6)÷60

= (9-6)÷60

= 3÷60

= 1/20 part of work

hence require time for fill tank 20 min

Answer 2

Answer:

20 minutes

Step-by-step explanation:

Lets the tank volume be v.

The first tap can fill the tank in 12 min.

for 12 min the tank volume = v

for 1 min the tank volume =v/12

The second tap con fill the tank in15 min.

for 15 min the tank volume= v

for 1 min the tank volume = v/15

The waste-pipe can empty the tank in 10 min.

for 10 min the the tank volume emptied= v

for 1 min the tank volume emptied= v/10

In what time will the tank be filled, if both are turned on and if the waste pipe has been left

open accidentally.

first tap filled water+second tap filled water-waste pipe removed water=v

let after t time it will be filled by opening all.

(first tap filled water in 1 minute+second tap filled water in 1 minute-waste pipe removed water in 1 minute)t =v

((v/12+v/15-v/10)t)= v

(v(1/12+1/15-1/10)t)=v

(v(5/60+4/60-6/10)t)=v

(v(3/60)t)=v

(v(3t/60))=v

3t/60=1

3t=60

☆t=20= 20 minutes

Hope it helps you.

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