one term of an arithmetic sequence is 45 and its common difference is 8. can the sum of any 15 terms be 2020?why?
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Given : one term of an arithmetic sequence is 45 and its common difference is 8
To find : Can sum of any 15 terms be 2020 ?
Solution:
One term is 45
Common difference = 8
any term can be of form 45 + 8k
where k is integer ( negative & positive both )
Now sum of any term will be of form
15 * 45 + 15 * 8 * k
= 675 + 120 * k
120 * k will always end with 0
& 675 ens with 5
Hence their sum will end with 5
5 - 0 = 5 & 5 + 0 = 5
Hence 675 + 120 * k ≠ 2020
Hence sum of any 15 terms can not be 2020
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