One third of a certain journey is covered at the rate of 25 km/hr. One fourth at the rate of 30 km/hr and the rest at 50 km/hr. What is the average speed of the whole journey
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Answered by
8
Hlo mate,
your answer is here,
d = total distance
t = total time
d/3 at 25
d/4 at 30
5d/12 at 50
-----------
t = (d/3)/25 + (d/4)/30 + (5d/12)/50
150t = 2d + 5d/4 + 5d/4 = 9d/2
300t = 9d
t = 3d/100
d = 100t/3
d/t = rate = 100/3
= 33 1/3 km/hr
-------------------
. 33 1/3 km/hr
I hope it helps you,....
your answer is here,
d = total distance
t = total time
d/3 at 25
d/4 at 30
5d/12 at 50
-----------
t = (d/3)/25 + (d/4)/30 + (5d/12)/50
150t = 2d + 5d/4 + 5d/4 = 9d/2
300t = 9d
t = 3d/100
d = 100t/3
d/t = rate = 100/3
= 33 1/3 km/hr
-------------------
. 33 1/3 km/hr
I hope it helps you,....
Answered by
1
d = total distance
t = total time
d/3 at 25
d/4 at 30
5d/12 at 50
-----------
t = (d/3)/25 + (d/4)/30 + (5d/12)/50
150t = 2d + 5d/4 + 5d/4 = 9d/2
300t = 9d
t = 3d/100
d = 100t/3
d/t = rate = 100/3
= 33 1/3 km/hr
t = total time
d/3 at 25
d/4 at 30
5d/12 at 50
-----------
t = (d/3)/25 + (d/4)/30 + (5d/12)/50
150t = 2d + 5d/4 + 5d/4 = 9d/2
300t = 9d
t = 3d/100
d = 100t/3
d/t = rate = 100/3
= 33 1/3 km/hr
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