Question

One third of a certain quantity exceeds one seventh of that quantity by 16. Find the quantity

Answer 1

Here is your answer
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Answer 2

We get the quantity as 84.

Given,

One-third of a certain quantity exceeds one-seventh of that quantity by 16

To Find,

The quantity

Solution,

Let the quantity be 'x'

Now, according to the question,

$\frac{x}{3} = \frac{x}{7} + 16$

$\frac{x}{3} - \frac{x}{7} = 16$

Taking LCM, we get

$\frac{7x}{21} - \frac{3x}{21} = 16$

$\frac{7x-3x}{21} = 16$

$\frac{4x}{21} = 16$

Cross-multiplying we get,

4x = 16 * 21

4x = 336

x = $\frac{336}{4}$

x = 84

Hence, we get the quantity as 84.

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