Question

One third of a number added to 9 is equal to 36. Find the number.​

Answer 1

AnswEr-:

• $\boxed {\sf{ The\:number\:is\:81.}}$

Explanation-:

$\underline{\mathrm{Given-: }}$

• One third of a number is added to 9 is equal to 36 .

$\underline{\mathrm{To\:Find-: }}$

• The number .

$\dag{\sf{\underline {Solution \:of\:question-: }}}$

$\underline{\mathrm{Let's \:Assume-: }}$

• The number be x .

• $\underbrace {\sf{Understanding \:the\:Concept-: }}$

• One third of a number is added to 9 is equal to 8

• Then ,

• $\longrightarrow {\sf{Equation \:Formed \:= \dfrac{1}{3} \times x + 9 = 36 }}$

$\dag{\sf{\underline {Now ,\:Solving \:for\:x \:in\:Equation-: }}}$

• $\longrightarrow {\sf{Equation \:Formed \:= \dfrac{1}{3} \times x + 9 = 36 }}$

• $\longrightarrow {\sf{ \dfrac{1}{3} \times x + 9 = 36 }}$

• $\longrightarrow {\sf{ \dfrac{1}{3} \times x = 36 - 9 }}$

• $\longrightarrow {\sf{ \dfrac{1}{3} \times x = 27 }}$

• $\longrightarrow {\sf{ x =\dfrac{ 27\times 3}{1} }}$

• $\longrightarrow {\sf{ x = 27\times 3 }}$

• $\longrightarrow {\sf{ x = 81 }}$

$\underline{\mathrm{Therefore-: }}$

• $\boxed {\sf{ x = 81 }}$

• Putting x = 81 .

• The number = x = 81

$\underline{\mathrm{Hence-: }}$

• $\boxed {\sf{ The\:number\:is\:81.}}$

_______________________________________

$\huge{\mathrm{Verification-: }}$

• $\longrightarrow {\sf{Equation \:Formed \:= \dfrac{1}{3} \times x + 9 = 36 }}$

• Here -:

• $\longrightarrow {\sf{ x = 81 }}$

• $\longrightarrow {\sf{ \dfrac{1}{3} \times 81 + 9 = 36 }}$

• $\longrightarrow {\sf{ \dfrac{1}{\cancel{3}} \times \cancel{81} + 9 = 36 }}$

• $\longrightarrow {\sf{ 27 + 9 = 36 }}$

• $\longrightarrow {\sf{ 36 = 36 }}$

Therefore,

• $\underline{\mathrm{LHS = \: RHS }}$

• $\underline{\mathrm{Hence, \: Verified}}$

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