Math, asked by 7703964078, 1 year ago

one third of a number exceeds one fifth of the number by 6 find the number

Answers

Answered by Thatsomeone
126
Let the number be x

one third of number = x/3

one fifth of number = x /5

by the condition given in your question we get equation

x/3 - x/5 = 6

5x - 3x /15 = 6

2x/15 = 6

2x = 15 × 6

x = 15 × 6/2

x = 15 × 3

x = 45

so your required number is 45
Answered by hukam0685
8

The number is 45.

Given:

  • 1/3rd of a number exceeds 1/5th of the number by 6.

To find:

  • Find the number.

Solution:

Step 1:

Let the number is x.

1/3rd of the number is : \frac{x}{3} \\

1/5th of the number is : \frac{x}{5}\\

Step 2:

Write the equation.

 \frac{x}{3}  =  \frac{x}{5}  + 6 \\

or

 \frac{x}{3}  -  \frac{x}{5}  = 6 \\

or

 \frac{5x - 3x}{15}  = 6 \\

or

 \frac{2x}{15}  = 6 \\

or

2x = 6 \times 15 \\

or

x = 3 \times 15 \\

or

\bf \red{x = 45} \\

Step 3:

Verification.

 \frac{45}{3}  =  \frac{45}{5}  + 6 \\

or

15 = 9 + 6 \\

or

\bf 15 = 15 \\

Hence verified.

Thus,

The number is 45.

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