Question

One third of a quantity exceeds one seventh of that quantity by 16 find the quantity

Answer 1

Answer:

Explanation:

Let “X” be the total quantity. X/3 of the quantity exceeds X/7 of that quantity by 16.

X/3=16+X/7

X/3-X/7=16

7X-3X/21=16

4X/21=16

X=84

Hope this helps :)