Question

one third of a two digits number is more than the one fourth it by 8 then find the sum of the digits of the number​

Answer 1

Step-by-step explanation:

let digit at ones place be y and at tens place be x.

required no. = 10x + y

a/q

1/3(10x+y) = 1/4(10x + y) + 8

(10x + y)÷3 -- (10x+y)÷4 =. 8

(40x + 4y -30x - 3y)÷12. =. 8

(10x+ y)÷12=8

10x+ y =96

thus the number is 96.