Question

One third of sum of two angles is 60º and one fourth of their difference is 28º. The angles are​

Answer 1

Answer:

let two angles are x,y

1/3(x+y)=60

x+y=60×3=180

1/4(x-y)=28

x-y=28×4=112

x+y=180

x-y=112

by eliminating y

2x=292

x=292/2=146

y=180-146=34

Answer 2

Answer:

angles : x,y

1/3(x+y) = 60°

1/4(x-y) = 28°

(x+y)/3 = 60

(x-y)/4 = 28

x+y = 60×3

x-y = 28×4

x+y = 180

x-y = 112

(-)(+) (-)

2y = 68

y = 68/2

y = 34°

(x+y)/3 = 60

(x+34) = 180

x = 180-34

x = 146°