Question

one third of the distance is covered with speed V1 and for the remaining distance this first one fourth of the remaining time is covered with speed v two and three fourth of the remaining time is covered with speed v 3

Answer 1

Answer:

Explanation:

Total distance S

Time to cover the first 1/3 of  S =  t1 = (S/3) / v1 = S/(3 v1)

Time to cover the second 1/3 of S = t2 = (S/3)/v2 = S/(3 v2)

Time to cover the last 1/3 of S = t3 = (S/3 ) / v3 = S/ (3v3)

Total time = t =  S/3 [ 1/v1 + 1/v2 + 1/v3 ]

Let v = average speed

v = S / t        So 1/v = t / S

1/ v = 1/3  [ 1/v1 + 1/v2 + 1/v3 ]

plzz mark me as brainlist