one third of the sum of two angles is 60° and quarter of their difference is 28°.find the two angles
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Answered by
5
(A + B)/3 = 60° .
So A+B = 180° ---(1)
(A-B)/4 = 28°
so A-B = 112° ---(2)
2A = 292. so A = 146° (by adding equations. )
B = 180° - A.
So B = 34° by using the equation (1).
So A+B = 180° ---(1)
(A-B)/4 = 28°
so A-B = 112° ---(2)
2A = 292. so A = 146° (by adding equations. )
B = 180° - A.
So B = 34° by using the equation (1).
kvnmurty:
:-)
Answered by
4
let the two angles be x,y
1/3(x+y)
1/3(x+y)
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