one third of the sum of two angles is 60° and quarter of their difference is 28°.find the two angles
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Solution:-
Let the two angles be 'x' and 'y'.
So, according to the question,
One third of the sum of two angles :- 1/3(x+y) = 60
x/3 + y/3 = 60 ......(1)
Quarter of their difference :- 1/4(x-y) = 28
x/4 - y/4 = 28...........(2)
Multiplying the equation (1) by 3 and equation (2) by 4, we get
x + y =180 .......(3) x - y = 112 ......(4)
Subtracting (4) from (3),
x + y = 180
x - y = 112
- + -
_________
2y = 68
_________
2y = 68
y = 34
Putting the value of y = 34 in the equation (3)
x + y = 180
x + 34 = 180
x = 180 - 34
x = 146
The two angles are 146° and 34°.
Answer
Let the two angles be 'x' and 'y'.
So, according to the question,
One third of the sum of two angles :- 1/3(x+y) = 60
x/3 + y/3 = 60 ......(1)
Quarter of their difference :- 1/4(x-y) = 28
x/4 - y/4 = 28...........(2)
Multiplying the equation (1) by 3 and equation (2) by 4, we get
x + y =180 .......(3) x - y = 112 ......(4)
Subtracting (4) from (3),
x + y = 180
x - y = 112
- + -
_________
2y = 68
_________
2y = 68
y = 34
Putting the value of y = 34 in the equation (3)
x + y = 180
x + 34 = 180
x = 180 - 34
x = 146
The two angles are 146° and 34°.
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