one third of the supplement of the angle is equal to 10 more than its complete find the angle
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let supplement of angle =180-x
and complement =90-x
1/3×180-x=10+90-x
=60-x=100-x
=60=100-(x+x)
=2x=100-60
=x=40/2
x=20
and complement =90-x
1/3×180-x=10+90-x
=60-x=100-x
=60=100-(x+x)
=2x=100-60
=x=40/2
x=20
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