Question

One thousand calories of heat are added to 100 gram of water at temprature 50C the resultant the resultant temprature of water will be

Answer 1

Explanation:

m = 100 g = 0.1 kg

heat (q) =1000 calories = 4200 joules

specific heat of water (c) = 4.2 kj/kg*c

q = m*c*(Tf-50)

4200= 0.1*4200*(Tf -50)

10 = Tf -50

Tf = 60 ℃

final temperature of water is 60℃