one ticket is drawn at random from a set of 20 digit number from 1 to 20 what is the probability that a number of the ticket drawn is divisible by 2 or 3
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let S be the sample space
= 1 2 3 4..........20
n (s)=20
event A = no. divisible by 2
A=2 4 6 8 10 12 14 16 18 20
n (A)=10
p (A) =n (A)/n(s)=10/20
probability of divisible by 2 is 1/2
event B = no. divisible by 3
B=3 6 9 12 15 18
n (B) =6
p (B)=n (B)/n (s)=6/20
and probability of divisible by 3is 3/10
= 1 2 3 4..........20
n (s)=20
event A = no. divisible by 2
A=2 4 6 8 10 12 14 16 18 20
n (A)=10
p (A) =n (A)/n(s)=10/20
probability of divisible by 2 is 1/2
event B = no. divisible by 3
B=3 6 9 12 15 18
n (B) =6
p (B)=n (B)/n (s)=6/20
and probability of divisible by 3is 3/10
shawnmendes99:
can you solve in full statements!
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total outcome =20
fav outcomes=lcm(2,3)=6
IE, 6,12,18
p(e)=3/20
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