Question

One top of the second tower from the tootor metus.
6. The length of shadow of a tower standing on the ground is found to be 60 metres more when
the sun's angle of elevation changes from 30° to 60%, let us find the height of the tower.
the foot of a​

Answer 1

Answer:

clearly length of shadow will be more when angle of elevation is less.

let length of shadow be x when angle of elevation was 60°. let the height of tower be h

then, tan60° = h/x

h/x = √3

x = h/√3........(1)

now angle of elevation is 30° and length of shadow is (x+60) m

tan30° = h/(x+60)

1/√3 = h/(x+60/

x+60 = √3h

x= √3h - 60.........(2)

from (1) and (2)

√3h - 60 = h/√3

multiplying both side by √3

3h - 60√3 = h

3h - h = 60√3

2h = 60√3

h = 30√3 m