Question

One toy cars was moving at a speed of 20cm/s after going a distance of 1 miter,the speed of the car stopped 50cm/s. determine the acceleration of the vehicle?

Answer 1

Answer:

Acceleration , a = 0.105 m/s²

Given

A toy car was moving at a speed of 20 cm/s . After going a distance of 1 meter,the speed of that car is 50 cm/s

To Find

Acceleration ,a

Solution

Initial speed , u = 20 cm/s = 0.2 m/s

Final speed , v = 50 cm/s = 0.5 m/s

Distance , s = 1 m

Acceleration , a = ? m/s²

Apply 3rd equation of motion .

⇒ v² - u² = 2as

⇒ 0.5² - 0.2² = 2a(1)

⇒ 0.25 - 0.04 = 2a

⇒ 0.21 = 2a

⇒ a = 0.105 m/s²

Answer 2

Answer:

Explanation:

by 3rd equation of motion

v² -u² = 2aS

where

v = final velocity = 50 cm/s = 0.5 m/s

u = initial velocity = 20cm/s = 0.2 m/s

a= acceleration

s = displacement = 1m

0.5² - 0.2² = 2 a (1)

0.25 - 0.04 = 2a

0.21 = 2a

a = 0.105 m/s²

hope it helps

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