Question

One train goes A to B in 6 hours and another train hoes B to A in 4 hours respectively. Both starts at 7 am. When will they meet ?

Who can answer this gets 100 points...​

Answer 1

Answer:

HEYY dear..

In 2.4 hrs..

hope it helps u...❤✌..

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Answer 2

Step-by-step explanation:

$\huge{\blue{\underline{\purple{\mathbb{Solution}}}}}\\ \\ Let \: distance \: between \: A \: and \: B \: be \:" x "\: km. \\ \\ Distance \: covered \: by \: train \: starting \: from \: A \: to \: B\: = x \: km \: \\ Time \: taken \: by \: train \: starting \: from \: A \: to \: B \: = 6 \: hours \\ Time \: taken \: by \: train \: starting \: from \: B\: to \: A \: = 4 \: hours \: \\ \\ Distance \: covered \: by \: both \: the \: trains \: are \: \\ equal \: as \: both \: train \: are \: moving \: towards \\ each \: other. \\ \\ \huge{\bold{ speed \: = \frac{distance \: }{time} }} \\ \\ Speed \: of \: the \: train \: starting \: from \: A \: to \: B \: = \frac{x}{6} \\ Speed \: of \: the \: train \: starting \: from \: B \: to \: A \: = \frac{x}{4} \\ \\ Let \: both \: the \: trains \: meets \:" y" \: hrs \: after \: 7 \: am \: . \\ Both \: the \: trains \: will \: meet \: at \: time \: (7 + y) -(1) \\ \\ \huge{\bold{ distance \: = speed \: \times time}} \\ \\ x = (\frac{x}{6} )y \: + (\frac{x}{4} )y \\ \\ x = ( \frac{y}{6} + \frac{y}{4} ) \\ \\ \frac{y}{6} + \frac{y}{4} = 1 \\ \\ \frac{5}{12} y = 1 \\ \\ y = \frac{12}{5} hours$

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