Question

One train travels 200m from a to b with 60 km/ph. and returns to a with 90kmph, what is the average of their speed?tcs

Answer 1

hey it's answer's formula =2v1v2/(v1+v2)

=2×60×90/(60+90)

=72km/h

Answer 2

Answer:

Explanation:

Concept:

Velocity:

The pace at which an object's position changes in relation to a frame of reference and time is what is meant by velocity. Although it may appear sophisticated, velocity is just the act of moving quickly in one direction. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction. Its SI equivalent is the meter per second (ms-1). A body is considered to be accelerating if the magnitude or direction of its velocity changes.

Speed:

The speed at which an object's location changes in any direction. The distance travelled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.

Given:

distance $= 200m$

velocity(v1) $=60km/hr$

velocity(v2) $= 90km/hr$

Find:

average speed

Solution:

Given v1 $= 60km/hr$

          v2 $= 90km/hr$

average speed = 2v1v2/v1+v2

                          $=2(\frac{60*90}{60+90} )$

                          $=2(\frac{5400}{150} )$

                          $=2(36)$

                           $=72km/hr$

Hence average speed is 72km/h

#SPJ2