Question

One 'U' stands for the mass of a.An atom of carbon -12 b.One twelfth of the carbon -12 c.One twelfth of the hydrogen atom d.One atom of any of the element

Answer 1

Answer:

Energy released in fission of one uranium nucleus, E=200 MeV per nucleus

∴ Energy released in fusion 1 kg U

236

, E

′

=200×

236

1000

×6.023×10

23

=5.1×10

26

MeV

⟹ E

′

=5.1×10

26

×1.6×10

−13

=8.16×10

13

J

Energy released during fusion of 1 kg hydrogen, E

H

2

=6.4×10

14

J

Thus ratio of energies,

E

′

E

H

2

=

8.16×10

13

6.4×10

14

≈7.28

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