Question

one unit contains five army officers and three naval officers, 2 Air Force officers, and second unit contains six army officers four naval officers, Three air force officers. if one unit is chosen at random and an officers is chosen. What is the probability that. 1: he is an army officer. 2: he is a naval officer. 3: he is an air force officer.​

Answer 1

Answer:

1: 0.48077

2: 0.3038

3: 0.2154

Given: unit 1( five army officers and three naval officers, 2 Air Force officers), total member =10

unit 2( six army officers four naval officers, Three air force officers), total members =13

To find: probability that.

1: he is an army officer.

2: he is a naval officer.

3: he is an air force officer.​

Solution:

1. here a total of two unit is there.

we randomly choose a unit

i.e probability of choosing a unit is 0.5

P( army officer) = 0.5*5/10 +0.5*6/13 =0.48077

2. P(naval officer)= 0.5*3/10 +0.5*4/13 =0.3038

3. P(air force officer)= 0.5*2/10 +0.5*3/13 = 0.2154