one upon 1 + sin square theta
+ one upon 1 + cosec square theta = 1
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0
sorry didn't understand ur question
Answered by
0
Step-by-step explanation:
1/(1+sin2A) + 1/(1+cosec2A)....(A= theta)
= 1/(1+sin2A) + 1/(1+1/sin2A)
= 1/(1+sin2A) + sin2A/(1+sin2A)
= (1+sin2A)/(1+sin2A)
= 1
proved
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