Math, asked by madhv8053, 11 hours ago

one upon sec theta minus tan theta equal to sec theta plus tan theta

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Answered by ROHANSINGHA99
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Answered by storiesinhindighost
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  • SolutionverifiedVerified by Toppr
  • SolutionverifiedVerified by TopprWe have,
  • SolutionverifiedVerified by TopprWe have,LHS =
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS =
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 ×
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθ
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS =
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan 2
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan 2 θ
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan 2 θsecθ+tanθ
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan 2 θsecθ+tanθ
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan 2 θsecθ+tanθ =
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan 2 θsecθ+tanθ = 1
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan 2 θsecθ+tanθ = 1secθ+tanθ
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan 2 θsecθ+tanθ = 1secθ+tanθ
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan 2 θsecθ+tanθ = 1secθ+tanθ [∵sec
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan 2 θsecθ+tanθ = 1secθ+tanθ [∵sec 2
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan 2 θsecθ+tanθ = 1secθ+tanθ [∵sec 2 θ−tan
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan 2 θsecθ+tanθ = 1secθ+tanθ [∵sec 2 θ−tan 2
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan 2 θsecθ+tanθ = 1secθ+tanθ [∵sec 2 θ−tan 2 θ=1]
  • SolutionverifiedVerified by TopprWe have,LHS = secθ−tanθ1 ⇒ LHS = secθ−tanθ1 × secθ+tanθsecθ+tanθ ⇒ LHS = sec 2 θ−tan 2 θsecθ+tanθ = 1secθ+tanθ [∵sec 2 θ−tan 2 θ=1]⇒ LHS = secθ+tanθ=RHS

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