One upon under root 7 minus under root 3
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Answer:
(√7+√3)/4
Explanation:
1/(√7-√3)
= (√7+√3)/[(√7-√3)(√7+√3)]
= (√7+√3)/[(√7)²-(√3)²]
= (√7+√3)/(7-3)
= (√7+√3)/4
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