One urn contains 4 white and 2 black balls. Second urn contains 5 white and 4 black balk. Two balls are transferred from the first tun to second urn. Then one ball is drawn from the second urn. Find the probability that it is white.
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Heya....❤❤❤
here is ur answer...
Lets rephrase that as "A randomly chosen ball from the first urn is transferred to the second urn", because that will make this problem actually doable!
Let the events be:
W = ball drawn is white;
T = ball transferred is white;
Well, basically we have
P(W)=P(W|T)P(T)+P(W|~T)P(~T)
=(6/10)*P(T)+(5/10)*P(~T)
=(6/10)*(4/9)+(5/10)*(5/9)
= (49/90)
hope it helps...
plzz mark me as brainliest my dear !!!
❤❤❤
here is ur answer...
Lets rephrase that as "A randomly chosen ball from the first urn is transferred to the second urn", because that will make this problem actually doable!
Let the events be:
W = ball drawn is white;
T = ball transferred is white;
Well, basically we have
P(W)=P(W|T)P(T)+P(W|~T)P(~T)
=(6/10)*P(T)+(5/10)*P(~T)
=(6/10)*(4/9)+(5/10)*(5/9)
= (49/90)
hope it helps...
plzz mark me as brainliest my dear !!!
❤❤❤
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